Solving ordinary differential equations

This file contains functions useful for solving differential equations which occur commonly in a 1st semester differential equations course. For another numerical solver see the ode_solver() function and the optional package Octave.

Solutions from the Maxima package can contain the three constants _C, _K1, and _K2 where the underscore is used to distinguish them from symbolic variables that the user might have used. You can substitute values for them, and make them into accessible usable symbolic variables, for example with var("_C").

Commands:

  • desolve() - Compute the “general solution” to a 1st or 2nd order ODE via Maxima.

  • desolve_laplace() - Solve an ODE using Laplace transforms via Maxima. Initial conditions are optional.

  • desolve_rk4() - Solve numerically an IVP for one first order equation, return list of points or plot.

  • desolve_system_rk4() - Solve numerically an IVP for a system of first order equations, return list of points.

  • desolve_odeint() - Solve numerically a system of first-order ordinary differential equations using odeint from scipy.integrate module.

  • desolve_system() - Solve a system of 1st order ODEs of any size using Maxima. Initial conditions are optional.

  • eulers_method() - Approximate solution to a 1st order DE, presented as a table.

  • eulers_method_2x2() - Approximate solution to a 1st order system of DEs, presented as a table.

  • eulers_method_2x2_plot() - Plot the sequence of points obtained from Euler’s method.

The following functions require the optional package tides:

  • desolve_mintides() - Numerical solution of a system of 1st order ODEs via the Taylor series integrator method implemented in TIDES.

  • desolve_tides_mpfr() - Arbitrary precision Taylor series integrator implemented in TIDES.

AUTHORS:

  • David Joyner (3-2006) - Initial version of functions

  • Marshall Hampton (7-2007) - Creation of Python module and testing

  • Robert Bradshaw (10-2008) - Some interface cleanup.

  • Robert Marik (10-2009) - Some bugfixes and enhancements

  • Miguel Marco (06-2014) - Tides desolvers

sage.calculus.desolvers.desolve(de, dvar, ics=None, ivar=None, show_method=False, contrib_ode=False, algorithm='maxima')

Solve a 1st or 2nd order linear ODE, including IVP and BVP.

INPUT:

  • de – an expression or equation representing the ODE

  • dvar – the dependent variable (hereafter called \(y\))

  • ics – (optional) the initial or boundary conditions

    • for a first-order equation, specify the initial \(x\) and \(y\)

    • for a second-order equation, specify the initial \(x\), \(y\), and \(dy/dx\), i.e. write \([x_0, y(x_0), y'(x_0)]\)

    • for a second-order boundary solution, specify initial and final \(x\) and \(y\) boundary conditions, i.e. write \([x_0, y(x_0), x_1, y(x_1)]\).

    • gives an error if the solution is not SymbolicEquation (as happens for example for a Clairaut equation)

  • ivar – (optional) the independent variable (hereafter called \(x\)), which must be specified if there is more than one independent variable in the equation

  • show_method – (optional) if True, then Sage returns pair [solution, method], where method is the string describing the method which has been used to get a solution (Maxima uses the following order for first order equations: linear, separable, exact (including exact with integrating factor), homogeneous, bernoulli, generalized homogeneous) - use carefully in class, see below the example of an equation which is separable but this property is not recognized by Maxima and the equation is solved as exact.

  • contrib_ode – (optional) if True, desolve allows to solve Clairaut, Lagrange, Riccati and some other equations. This may take a long time and is thus turned off by default. Initial conditions can be used only if the result is one SymbolicEquation (does not contain a singular solution, for example).

  • algorithm – (default: 'maxima') one of

    • 'maxima' - use maxima

    • 'fricas' - use FriCAS (the optional fricas spkg has to be installed)

OUTPUT:

In most cases return a SymbolicEquation which defines the solution implicitly. If the result is in the form \(y(x)=\ldots\) (happens for linear eqs.), return the right-hand side only. The possible constant solutions of separable ODEs are omitted.

Note

Use desolve? <tab> if the output in the Sage notebook is truncated.

EXAMPLES:

sage: x = var('x')
sage: y = function('y')(x)
sage: desolve(diff(y,x) + y - 1, y)
(_C + e^x)*e^(-x)

sage: f = desolve(diff(y,x) + y - 1, y, ics=[10,2]); f
(e^10 + e^x)*e^(-x)

sage: plot(f)
Graphics object consisting of 1 graphics primitive

We can also solve second-order differential equations:

sage: x = var('x')
sage: y = function('y')(x)
sage: de = diff(y,x,2) - y == x
sage: desolve(de, y)
_K2*e^(-x) + _K1*e^x - x

sage: f = desolve(de, y, [10,2,1]); f
-x + 7*e^(x - 10) + 5*e^(-x + 10)

sage: f(x=10)
2

sage: diff(f,x)(x=10)
1

sage: de = diff(y,x,2) + y == 0
sage: desolve(de, y)
_K2*cos(x) + _K1*sin(x)

sage: desolve(de, y, [0,1,pi/2,4])
cos(x) + 4*sin(x)

sage: desolve(y*diff(y,x)+sin(x)==0,y)
-1/2*y(x)^2 == _C - cos(x)

Clairaut equation: general and singular solutions:

sage: desolve(diff(y,x)^2+x*diff(y,x)-y==0,y,contrib_ode=True,show_method=True)
[[y(x) == _C^2 + _C*x, y(x) == -1/4*x^2], 'clairault']

For equations involving more variables we specify an independent variable:

sage: a,b,c,n=var('a b c n')
sage: desolve(x^2*diff(y,x)==a+b*x^n+c*x^2*y^2,y,ivar=x,contrib_ode=True)
[[y(x) == 0, (b*x^(n - 2) + a/x^2)*c^2*u == 0]]

sage: desolve(x^2*diff(y,x)==a+b*x^n+c*x^2*y^2,y,ivar=x,contrib_ode=True,show_method=True)
[[[y(x) == 0, (b*x^(n - 2) + a/x^2)*c^2*u == 0]], 'riccati']

Higher order equations, not involving independent variable:

sage: desolve(diff(y,x,2)+y*(diff(y,x,1))^3==0,y).expand()
1/6*y(x)^3 + _K1*y(x) == _K2 + x

sage: desolve(diff(y,x,2)+y*(diff(y,x,1))^3==0,y,[0,1,1,3]).expand()
1/6*y(x)^3 - 5/3*y(x) == x - 3/2

sage: desolve(diff(y,x,2)+y*(diff(y,x,1))^3==0,y,[0,1,1,3],show_method=True)
[1/6*y(x)^3 - 5/3*y(x) == x - 3/2, 'freeofx']

Separable equations - Sage returns solution in implicit form:

sage: desolve(diff(y,x)*sin(y) == cos(x),y)
-cos(y(x)) == _C + sin(x)

sage: desolve(diff(y,x)*sin(y) == cos(x),y,show_method=True)
[-cos(y(x)) == _C + sin(x), 'separable']

sage: desolve(diff(y,x)*sin(y) == cos(x),y,[pi/2,1])
-cos(y(x)) == -cos(1) + sin(x) - 1

Linear equation - Sage returns the expression on the right hand side only:

sage: desolve(diff(y,x)+(y) == cos(x),y)
1/2*((cos(x) + sin(x))*e^x + 2*_C)*e^(-x)

sage: desolve(diff(y,x)+(y) == cos(x),y,show_method=True)
[1/2*((cos(x) + sin(x))*e^x + 2*_C)*e^(-x), 'linear']

sage: desolve(diff(y,x)+(y) == cos(x),y,[0,1])
1/2*(cos(x)*e^x + e^x*sin(x) + 1)*e^(-x)

This ODE with separated variables is solved as exact. Explanation - factor does not split \(e^{x-y}\) in Maxima into \(e^{x}e^{y}\):

sage: desolve(diff(y,x)==exp(x-y),y,show_method=True)
[-e^x + e^y(x) == _C, 'exact']

You can solve Bessel equations, also using initial conditions, but you cannot put (sometimes desired) the initial condition at \(x=0\), since this point is a singular point of the equation. Anyway, if the solution should be bounded at \(x=0\), then _K2=0.

sage: desolve(x^2*diff(y,x,x)+x*diff(y,x)+(x^2-4)*y==0,y)
_K1*bessel_J(2, x) + _K2*bessel_Y(2, x)

Example of difficult ODE producing an error:

sage: desolve(sqrt(y)*diff(y,x)+e^(y)+cos(x)-sin(x+y)==0,y) # not tested
Traceback (click to the left for traceback)
...
NotImplementedError, "Maxima was unable to solve this ODE. Consider to set option contrib_ode to True."

Another difficult ODE with error - moreover, it takes a long time:

sage: desolve(sqrt(y)*diff(y,x)+e^(y)+cos(x)-sin(x+y)==0,y,contrib_ode=True) # not tested

Some more types of ODEs:

sage: desolve(x*diff(y,x)^2-(1+x*y)*diff(y,x)+y==0,y,contrib_ode=True,show_method=True)
[[y(x) == _C + log(x), y(x) == _C*e^x], 'factor']

sage: desolve(diff(y,x)==(x+y)^2,y,contrib_ode=True,show_method=True)
[[[x == _C - arctan(sqrt(t)), y(x) == -x - sqrt(t)], [x == _C + arctan(sqrt(t)), y(x) == -x + sqrt(t)]], 'lagrange']

These two examples produce an error (as expected, Maxima 5.18 cannot solve equations from initial conditions). Maxima 5.18 returns false answer in this case!

sage: desolve(diff(y,x,2)+y*(diff(y,x,1))^3==0,y,[0,1,2]).expand() # not tested
Traceback (click to the left for traceback)
...
NotImplementedError, "Maxima was unable to solve this ODE. Consider to set option contrib_ode to True."

sage: desolve(diff(y,x,2)+y*(diff(y,x,1))^3==0,y,[0,1,2],show_method=True) # not tested
Traceback (click to the left for traceback)
...
NotImplementedError, "Maxima was unable to solve this ODE. Consider to set option contrib_ode to True."

Second order linear ODE:

sage: desolve(diff(y,x,2)+2*diff(y,x)+y == cos(x),y)
(_K2*x + _K1)*e^(-x) + 1/2*sin(x)

sage: desolve(diff(y,x,2)+2*diff(y,x)+y == cos(x),y,show_method=True)
[(_K2*x + _K1)*e^(-x) + 1/2*sin(x), 'variationofparameters']

sage: desolve(diff(y,x,2)+2*diff(y,x)+y == cos(x),y,[0,3,1])
1/2*(7*x + 6)*e^(-x) + 1/2*sin(x)

sage: desolve(diff(y,x,2)+2*diff(y,x)+y == cos(x),y,[0,3,1],show_method=True)
[1/2*(7*x + 6)*e^(-x) + 1/2*sin(x), 'variationofparameters']

sage: desolve(diff(y,x,2)+2*diff(y,x)+y == cos(x),y,[0,3,pi/2,2])
3*(x*(e^(1/2*pi) - 2)/pi + 1)*e^(-x) + 1/2*sin(x)

sage: desolve(diff(y,x,2)+2*diff(y,x)+y == cos(x),y,[0,3,pi/2,2],show_method=True)
[3*(x*(e^(1/2*pi) - 2)/pi + 1)*e^(-x) + 1/2*sin(x), 'variationofparameters']

sage: desolve(diff(y,x,2)+2*diff(y,x)+y == 0,y)
(_K2*x + _K1)*e^(-x)

sage: desolve(diff(y,x,2)+2*diff(y,x)+y == 0,y,show_method=True)
[(_K2*x + _K1)*e^(-x), 'constcoeff']

sage: desolve(diff(y,x,2)+2*diff(y,x)+y == 0,y,[0,3,1])
(4*x + 3)*e^(-x)

sage: desolve(diff(y,x,2)+2*diff(y,x)+y == 0,y,[0,3,1],show_method=True)
[(4*x + 3)*e^(-x), 'constcoeff']

sage: desolve(diff(y,x,2)+2*diff(y,x)+y == 0,y,[0,3,pi/2,2])
(2*x*(2*e^(1/2*pi) - 3)/pi + 3)*e^(-x)

sage: desolve(diff(y,x,2)+2*diff(y,x)+y == 0,y,[0,3,pi/2,2],show_method=True)
[(2*x*(2*e^(1/2*pi) - 3)/pi + 3)*e^(-x), 'constcoeff']

Using algorithm='fricas' we can invoke the differential equation solver from FriCAS. For example, it can solve higher order linear equations:

sage: de = x^3*diff(y, x, 3) + x^2*diff(y, x, 2) - 2*x*diff(y, x) + 2*y - 2*x^4
sage: Y = desolve(de, y, algorithm="fricas"); Y               # optional - fricas
(2*x^3 - 3*x^2 + 1)*_C0/x + (x^3 - 1)*_C1/x
 + (x^3 - 3*x^2 - 1)*_C2/x + 1/15*(x^5 - 10*x^3 + 20*x^2 + 4)/x

The initial conditions are then interpreted as \([x_0, y(x_0), y'(x_0), \ldots, y^(n)(x_0)]\):

sage: Y = desolve(de, y, ics=[1,3,7], algorithm="fricas"); Y  # optional - fricas
1/15*(x^5 + 15*x^3 + 50*x^2 - 21)/x

FriCAS can also solve some non-linear equations:

sage: de = diff(y, x) == y / (x+y*log(y))
sage: Y = desolve(de, y, algorithm="fricas"); Y               # optional - fricas
1/2*(log(y(x))^2*y(x) - 2*x)/y(x)

AUTHORS:

  • David Joyner (1-2006)

  • Robert Bradshaw (10-2008)

  • Robert Marik (10-2009)

sage.calculus.desolvers.desolve_laplace(de, dvar, ics=None, ivar=None)

Solve an ODE using Laplace transforms. Initial conditions are optional.

INPUT:

  • de - a lambda expression representing the ODE (e.g. de = diff(y,x,2) == diff(y,x)+sin(x))

  • dvar - the dependent variable (e.g. y)

  • ivar - (optional) the independent variable (hereafter called \(x\)), which must be specified if there is more than one independent variable in the equation.

  • ics - a list of numbers representing initial conditions, (e.g. f(0)=1, f'(0)=2 corresponds to ics = [0,1,2])

OUTPUT:

Solution of the ODE as symbolic expression

EXAMPLES:

sage: u=function('u')(x)
sage: eq = diff(u,x) - exp(-x) - u == 0
sage: desolve_laplace(eq,u)
1/2*(2*u(0) + 1)*e^x - 1/2*e^(-x)

We can use initial conditions:

sage: desolve_laplace(eq,u,ics=[0,3])
-1/2*e^(-x) + 7/2*e^x

The initial conditions do not persist in the system (as they persisted in previous versions):

sage: desolve_laplace(eq,u)
1/2*(2*u(0) + 1)*e^x - 1/2*e^(-x)

sage: f=function('f')(x)
sage: eq = diff(f,x) + f == 0
sage: desolve_laplace(eq,f,[0,1])
e^(-x)

sage: x = var('x')
sage: f = function('f')(x)
sage: de = diff(f,x,x) - 2*diff(f,x) + f
sage: desolve_laplace(de,f)
-x*e^x*f(0) + x*e^x*D[0](f)(0) + e^x*f(0)

sage: desolve_laplace(de,f,ics=[0,1,2])
x*e^x + e^x

AUTHORS:

  • David Joyner (1-2006,8-2007)

  • Robert Marik (10-2009)

sage.calculus.desolvers.desolve_mintides(f, ics, initial, final, delta, tolrel=1e-16, tolabs=1e-16)

Solve numerically a system of first order differential equations using the taylor series integrator implemented in mintides.

INPUT:

  • f – symbolic function. Its first argument will be the independent variable. Its output should be de derivatives of the dependent variables.

  • ics – a list or tuple with the initial conditions.

  • initial – the starting value for the independent variable.

  • final – the final value for the independent value.

  • delta – the size of the steps in the output.

  • tolrel – the relative tolerance for the method.

  • tolabs – the absolute tolerance for the method.

OUTPUT:

  • A list with the positions of the IVP.

EXAMPLES:

We integrate a periodic orbit of the Kepler problem along 50 periods:

sage: var('t,x,y,X,Y')
(t, x, y, X, Y)
sage: f(t,x,y,X,Y)=[X, Y, -x/(x^2+y^2)^(3/2), -y/(x^2+y^2)^(3/2)]
sage: ics = [0.8, 0, 0, 1.22474487139159]
sage: t = 100*pi
sage: sol = desolve_mintides(f, ics, 0, t, t, 1e-12, 1e-12) # optional -tides
sage: sol # optional -tides # abs tol 1e-5
[[0.000000000000000,
0.800000000000000,
0.000000000000000,
0.000000000000000,
1.22474487139159],
[314.159265358979,
0.800000000028622,
-5.91973525754241e-9,
7.56887091890590e-9,
1.22474487136329]]

ALGORITHM:

Uses TIDES.

REFERENCES:

sage.calculus.desolvers.desolve_odeint(des, ics, times, dvars, ivar=None, compute_jac=False, args=(), rtol=None, atol=None, tcrit=None, h0=0.0, hmax=0.0, hmin=0.0, ixpr=0, mxstep=0, mxhnil=0, mxordn=12, mxords=5, printmessg=0)

Solve numerically a system of first-order ordinary differential equations using odeint from scipy.integrate module.

INPUT:

  • des – right hand sides of the system

  • ics – initial conditions

  • times – a sequence of time points in which the solution must be found

  • dvars – dependent variables. ATTENTION: the order must be the same as in des, that means: d(dvars[i])/dt=des[i]

  • ivar – independent variable, optional.

  • compute_jac – boolean. If True, the Jacobian of des is computed and used during the integration of stiff systems. Default value is False.

Other Parameters (taken from the documentation of odeint function from scipy.integrate module.)

  • rtol, atol : float The input parameters rtol and atol determine the error control performed by the solver. The solver will control the vector, \(e\), of estimated local errors in \(y\), according to an inequality of the form:

    max-norm of (e / ewt) <= 1

    where ewt is a vector of positive error weights computed as:

    ewt = rtol * abs(y) + atol

    rtol and atol can be either vectors the same length as \(y\) or scalars.

  • tcrit : array Vector of critical points (e.g. singularities) where integration care should be taken.

  • h0 : float, (0: solver-determined) The step size to be attempted on the first step.

  • hmax : float, (0: solver-determined) The maximum absolute step size allowed.

  • hmin : float, (0: solver-determined) The minimum absolute step size allowed.

  • ixpr : boolean. Whether to generate extra printing at method switches.

  • mxstep : integer, (0: solver-determined) Maximum number of (internally defined) steps allowed for each integration point in t.

  • mxhnil : integer, (0: solver-determined) Maximum number of messages printed.

  • mxordn : integer, (0: solver-determined) Maximum order to be allowed for the nonstiff (Adams) method.

  • mxords : integer, (0: solver-determined) Maximum order to be allowed for the stiff (BDF) method.

OUTPUT:

Return a list with the solution of the system at each time in times.

EXAMPLES:

Lotka Volterra Equations:

sage: from sage.calculus.desolvers import desolve_odeint
sage: x,y=var('x,y')
sage: f=[x*(1-y),-y*(1-x)]
sage: sol=desolve_odeint(f,[0.5,2],srange(0,10,0.1),[x,y])
sage: p=line(zip(sol[:,0],sol[:,1]))
sage: p.show()

Lorenz Equations:

sage: x,y,z=var('x,y,z')
sage: # Next we define the parameters
sage: sigma=10
sage: rho=28
sage: beta=8/3
sage: # The Lorenz equations
sage: lorenz=[sigma*(y-x),x*(rho-z)-y,x*y-beta*z]
sage: # Time and initial conditions
sage: times=srange(0,50.05,0.05)
sage: ics=[0,1,1]
sage: sol=desolve_odeint(lorenz,ics,times,[x,y,z],rtol=1e-13,atol=1e-14)

One-dimensional stiff system:

sage: y= var('y')
sage: epsilon=0.01
sage: f=y^2*(1-y)
sage: ic=epsilon
sage: t=srange(0,2/epsilon,1)
sage: sol=desolve_odeint(f,ic,t,y,rtol=1e-9,atol=1e-10,compute_jac=True)
sage: p=points(zip(t,sol))
sage: p.show()

Another stiff system with some optional parameters with no default value:

sage: y1,y2,y3=var('y1,y2,y3')
sage: f1=77.27*(y2+y1*(1-8.375*1e-6*y1-y2))
sage: f2=1/77.27*(y3-(1+y1)*y2)
sage: f3=0.16*(y1-y3)
sage: f=[f1,f2,f3]
sage: ci=[0.2,0.4,0.7]
sage: t=srange(0,10,0.01)
sage: v=[y1,y2,y3]
sage: sol=desolve_odeint(f,ci,t,v,rtol=1e-3,atol=1e-4,h0=0.1,hmax=1,hmin=1e-4,mxstep=1000,mxords=17)

AUTHOR:

  • Oriol Castejon (05-2010)

sage.calculus.desolvers.desolve_rk4(de, dvar, ics=None, ivar=None, end_points=None, step=0.1, output='list', **kwds)

Solve numerically one first-order ordinary differential equation.

INPUT:

Input is similar to desolve command. The differential equation can be written in a form close to the plot_slope_field or desolve command.

  • Variant 1 (function in two variables)

    • de - right hand side, i.e. the function \(f(x,y)\) from ODE \(y'=f(x,y)\)

    • dvar - dependent variable (symbolic variable declared by var)

  • Variant 2 (symbolic equation)

    • de - equation, including term with diff(y,x)

    • dvar - dependent variable (declared as function of independent variable)

  • Other parameters

    • ivar - should be specified, if there are more variables or if the equation is autonomous

    • ics - initial conditions in the form [x0,y0]

    • end_points - the end points of the interval

      • if end_points is a or [a], we integrate between min(ics[0],a) and max(ics[0],a)

      • if end_points is None, we use end_points=ics[0]+10

      • if end_points is [a,b] we integrate between min(ics[0], a) and max(ics[0], b)

    • step - (optional, default:0.1) the length of the step (positive number)

    • output - (optional, default: 'list') one of 'list', 'plot', 'slope_field' (graph of the solution with slope field)

OUTPUT:

Return a list of points, or plot produced by list_plot, optionally with slope field.

See also

ode_solver().

EXAMPLES:

sage: from sage.calculus.desolvers import desolve_rk4

Variant 2 for input - more common in numerics:

sage: x,y = var('x,y')
sage: desolve_rk4(x*y*(2-y),y,ics=[0,1],end_points=1,step=0.5)
[[0, 1], [0.5, 1.12419127424558], [1.0, 1.461590162288825]]

Variant 1 for input - we can pass ODE in the form used by desolve function In this example we integrate backwards, since end_points < ics[0]:

sage: y = function('y')(x)
sage: desolve_rk4(diff(y,x)+y*(y-1) == x-2,y,ics=[1,1],step=0.5, end_points=0)
[[0.0, 8.904257108962112], [0.5, 1.909327945361535], [1, 1]]

Here we show how to plot simple pictures. For more advanced applications use list_plot instead. To see the resulting picture use show(P) in Sage notebook.

sage: x,y = var('x,y')
sage: P=desolve_rk4(y*(2-y),y,ics=[0,.1],ivar=x,output='slope_field',end_points=[-4,6],thickness=3)

ALGORITHM:

4th order Runge-Kutta method. Wrapper for command rk in Maxima’s dynamics package. Perhaps could be faster by using fast_float instead.

AUTHORS:

  • Robert Marik (10-2009)

sage.calculus.desolvers.desolve_rk4_determine_bounds(ics, end_points=None)

Used to determine bounds for numerical integration.

  • If end_points is None, the interval for integration is from ics[0] to ics[0]+10

  • If end_points is a or [a], the interval for integration is from min(ics[0],a) to max(ics[0],a)

  • If end_points is [a,b], the interval for integration is from min(ics[0],a) to max(ics[0],b)

EXAMPLES:

sage: from sage.calculus.desolvers import desolve_rk4_determine_bounds
sage: desolve_rk4_determine_bounds([0,2],1)
(0, 1)

sage: desolve_rk4_determine_bounds([0,2])
(0, 10)

sage: desolve_rk4_determine_bounds([0,2],[-2])
(-2, 0)

sage: desolve_rk4_determine_bounds([0,2],[-2,4])
(-2, 4)
sage.calculus.desolvers.desolve_system(des, vars, ics=None, ivar=None, algorithm='maxima')

Solve a system of any size of 1st order ODEs. Initial conditions are optional.

One dimensional systems are passed to desolve_laplace().

INPUT:

  • des – list of ODEs

  • vars – list of dependent variables

  • ics – (optional) list of initial values for ivar and vars; if ics is defined, it should provide initial conditions for each variable, otherwise an exception would be raised

  • ivar – (optional) the independent variable, which must be specified if there is more than one independent variable in the equation

  • algorithm – (default: 'maxima') one of

    • 'maxima' - use maxima

    • 'fricas' - use FriCAS (the optional fricas spkg has to be installed)

EXAMPLES:

sage: t = var('t')
sage: x = function('x')(t)
sage: y = function('y')(t)
sage: de1 = diff(x,t) + y - 1 == 0
sage: de2 = diff(y,t) - x + 1 == 0
sage: desolve_system([de1, de2], [x,y])
[x(t) == (x(0) - 1)*cos(t) - (y(0) - 1)*sin(t) + 1,
 y(t) == (y(0) - 1)*cos(t) + (x(0) - 1)*sin(t) + 1]

The same system solved using FriCAS:

sage: desolve_system([de1, de2], [x,y], algorithm='fricas')  # optional - fricas
[x(t) == _C0*cos(t) + cos(t)^2 + _C1*sin(t) + sin(t)^2,
 y(t) == -_C1*cos(t) + _C0*sin(t) + 1]

Now we give some initial conditions:

sage: sol = desolve_system([de1, de2], [x,y], ics=[0,1,2]); sol
[x(t) == -sin(t) + 1, y(t) == cos(t) + 1]

sage: solnx, solny = sol[0].rhs(), sol[1].rhs()
sage: plot([solnx,solny],(0,1))  # not tested
sage: parametric_plot((solnx,solny),(0,1))  # not tested

AUTHORS:

  • Robert Bradshaw (10-2008)

  • Sergey Bykov (10-2014)

sage.calculus.desolvers.desolve_system_rk4(des, vars, ics=None, ivar=None, end_points=None, step=0.1)

Solve numerically a system of first-order ordinary differential equations using the 4th order Runge-Kutta method. Wrapper for Maxima command rk.

INPUT:

input is similar to desolve_system and desolve_rk4 commands

  • des - right hand sides of the system

  • vars - dependent variables

  • ivar - (optional) should be specified, if there are more variables or if the equation is autonomous and the independent variable is missing

  • ics - initial conditions in the form [x0,y01,y02,y03,....]

  • end_points - the end points of the interval

    • if end_points is a or [a], we integrate on between min(ics[0], a) and max(ics[0], a)

    • if end_points is None, we use end_points=ics[0]+10

    • if end_points is [a,b] we integrate on between min(ics[0], a) and max(ics[0], b)

  • step – (optional, default: 0.1) the length of the step

OUTPUT:

Return a list of points.

See also

ode_solver().

EXAMPLES:

sage: from sage.calculus.desolvers import desolve_system_rk4

Lotka Volterra system:

sage: from sage.calculus.desolvers import desolve_system_rk4
sage: x,y,t=var('x y t')
sage: P=desolve_system_rk4([x*(1-y),-y*(1-x)],[x,y],ics=[0,0.5,2],ivar=t,end_points=20)
sage: Q=[ [i,j] for i,j,k in P]
sage: LP=list_plot(Q)

sage: Q=[ [j,k] for i,j,k in P]
sage: LP=list_plot(Q)

ALGORITHM:

4th order Runge-Kutta method. Wrapper for command rk in Maxima’s dynamics package. Perhaps could be faster by using fast_float instead.

AUTHOR:

  • Robert Marik (10-2009)

sage.calculus.desolvers.desolve_tides_mpfr(f, ics, initial, final, delta, tolrel=1e-16, tolabs=1e-16, digits=50)

Solve numerically a system of first order differential equations using the taylor series integrator in arbitrary precision implemented in tides.

INPUT:

  • f – symbolic function. Its first argument will be the independent variable. Its output should be de derivatives of the dependent variables.

  • ics – a list or tuple with the initial conditions.

  • initial – the starting value for the independent variable.

  • final – the final value for the independent value.

  • delta – the size of the steps in the output.

  • tolrel – the relative tolerance for the method.

  • tolabs – the absolute tolerance for the method.

  • digits – the digits of precision used in the computation.

OUTPUT:

  • A list with the positions of the IVP.

EXAMPLES:

We integrate the Lorenz equations with Saltzman values for the parameters along 10 periodic orbits with 100 digits of precision:

sage: var('t,x,y,z')
(t, x, y, z)
sage: s = 10
sage: r = 28
sage: b = 8/3
sage: f(t,x,y,z)= [s*(y-x),x*(r-z)-y,x*y-b*z]
sage: x0 = -13.7636106821342005250144010543616538641008648540923684535378642921202827747268115852940239346395038284
sage: y0 = -19.5787519424517955388380414460095588661142400534276438649791334295426354746147526415973165506704676171
sage: z0 = 27
sage: T = 15.586522107161747275678702092126960705284805489972439358895215783190198756258880854355851082660142374
sage: sol = desolve_tides_mpfr(f, [x0, y0, z0], 0, T, T, 1e-100, 1e-100, 100) # optional - tides
sage: sol # optional -tides # abs tol 1e-50
[[0.000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000,
-13.7636106821342005250144010543616538641008648540923684535378642921202827747268115852940239346395038,
-19.5787519424517955388380414460095588661142400534276438649791334295426354746147526415973165506704676,
27.0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000],
[15.5865221071617472756787020921269607052848054899724393588952157831901987562588808543558510826601424,
-13.7636106821342005250144010543616538641008648540923684535378642921202827747268115852940239346315658,
-19.5787519424517955388380414460095588661142400534276438649791334295426354746147526415973165506778440,
26.9999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999636628]]

ALGORITHM:

Uses TIDES.

Warning

This requires the package tides.

REFERENCES:

sage.calculus.desolvers.eulers_method(f, x0, y0, h, x1, algorithm='table')

This implements Euler’s method for finding numerically the solution of the 1st order ODE \(y' = f(x,y)\), \(y(a)=c\). The x column of the table increments from \(x_0\) to \(x_1\) by \(h\) (so \((x_1-x_0)/h\) must be an integer). In the y column, the new \(y\)-value equals the old \(y\)-value plus the corresponding entry in the last column.

Note

This function is for pedagogical purposes only.

EXAMPLES:

sage: from sage.calculus.desolvers import eulers_method
sage: x,y = PolynomialRing(QQ,2,"xy").gens()
sage: eulers_method(5*x+y-5,0,1,1/2,1)
     x                    y                  h*f(x,y)
     0                    1                   -2
   1/2                   -1                 -7/4
     1                -11/4                -11/8

sage: x,y = PolynomialRing(QQ,2,"xy").gens()
sage: eulers_method(5*x+y-5,0,1,1/2,1,algorithm="none")
[[0, 1], [1/2, -1], [1, -11/4], [3/2, -33/8]]

sage: RR = RealField(sci_not=0, prec=4, rnd='RNDU')
sage: x,y = PolynomialRing(RR,2,"xy").gens()
sage: eulers_method(5*x+y-5,0,1,1/2,1,algorithm="None")
[[0, 1], [1/2, -1.0], [1, -2.7], [3/2, -4.0]]

sage: RR = RealField(sci_not=0, prec=4, rnd='RNDU')
sage: x,y=PolynomialRing(RR,2,"xy").gens()
sage: eulers_method(5*x+y-5,0,1,1/2,1)
     x                    y                  h*f(x,y)
     0                    1                 -2.0
   1/2                 -1.0                 -1.7
     1                 -2.7                 -1.3

sage: x,y=PolynomialRing(QQ,2,"xy").gens()
sage: eulers_method(5*x+y-5,1,1,1/3,2)
         x                    y                  h*f(x,y)
         1                    1                  1/3
       4/3                  4/3                    1
       5/3                  7/3                 17/9
         2                 38/9                83/27

sage: eulers_method(5*x+y-5,0,1,1/2,1,algorithm="none")
[[0, 1], [1/2, -1], [1, -11/4], [3/2, -33/8]]

sage: pts = eulers_method(5*x+y-5,0,1,1/2,1,algorithm="none")
sage: P1 = list_plot(pts)
sage: P2 = line(pts)
sage: (P1+P2).show()

AUTHORS:

  • David Joyner

sage.calculus.desolvers.eulers_method_2x2(f, g, t0, x0, y0, h, t1, algorithm='table')

This implements Euler’s method for finding numerically the solution of the 1st order system of two ODEs

\[\begin{split}\begin{aligned} x' &= f(t, x, y), x(t_0)=x_0 \\ y' &= g(t, x, y), y(t_0)=y_0. \end{aligned}\end{split}\]

The t column of the table increments from \(t_0\) to \(t_1\) by \(h\) (so \(\frac{t_1-t_0}{h}\) must be an integer). In the x column, the new \(x\)-value equals the old \(x\)-value plus the corresponding entry in the next (third) column. In the y column, the new \(y\)-value equals the old \(y\)-value plus the corresponding entry in the next (last) column.

Note

This function is for pedagogical purposes only.

EXAMPLES:

sage: from sage.calculus.desolvers import eulers_method_2x2
sage: t, x, y = PolynomialRing(QQ,3,"txy").gens()
sage: f = x+y+t; g = x-y
sage: eulers_method_2x2(f,g, 0, 0, 0, 1/3, 1,algorithm="none")
[[0, 0, 0], [1/3, 0, 0], [2/3, 1/9, 0], [1, 10/27, 1/27], [4/3, 68/81, 4/27]]

sage: eulers_method_2x2(f,g, 0, 0, 0, 1/3, 1)
     t                    x                h*f(t,x,y)                    y           h*g(t,x,y)
     0                    0                         0                    0                    0
   1/3                    0                       1/9                    0                    0
   2/3                  1/9                      7/27                    0                 1/27
     1                10/27                     38/81                 1/27                  1/9

sage: RR = RealField(sci_not=0, prec=4, rnd='RNDU')
sage: t,x,y=PolynomialRing(RR,3,"txy").gens()
sage: f = x+y+t; g = x-y
sage: eulers_method_2x2(f,g, 0, 0, 0, 1/3, 1)
     t                    x                h*f(t,x,y)                    y           h*g(t,x,y)
     0                    0                      0.00                    0                 0.00
   1/3                 0.00                      0.13                 0.00                 0.00
   2/3                 0.13                      0.29                 0.00                0.043
     1                 0.41                      0.57                0.043                 0.15

To numerically approximate \(y(1)\), where \((1+t^2)y''+y'-y=0\), \(y(0)=1\), \(y'(0)=-1\), using 4 steps of Euler’s method, first convert to a system: \(y_1' = y_2\), \(y_1(0)=1\); \(y_2' = \frac{y_1-y_2}{1+t^2}\), \(y_2(0)=-1\).:

sage: RR = RealField(sci_not=0, prec=4, rnd='RNDU')
sage: t, x, y=PolynomialRing(RR,3,"txy").gens()
sage: f = y; g = (x-y)/(1+t^2)
sage: eulers_method_2x2(f,g, 0, 1, -1, 1/4, 1)
    t                    x                h*f(t,x,y)                    y           h*g(t,x,y)
    0                    1                     -0.25                   -1                 0.50
  1/4                 0.75                     -0.12                -0.50                 0.29
  1/2                 0.63                    -0.054                -0.21                 0.19
  3/4                 0.63                   -0.0078               -0.031                 0.11
    1                 0.63                     0.020                0.079                0.071

To numerically approximate \(y(1)\), where \(y''+ty'+y=0\), \(y(0)=1\), \(y'(0)=0\):

sage: t,x,y=PolynomialRing(RR,3,"txy").gens()
sage: f = y; g = -x-y*t
sage: eulers_method_2x2(f,g, 0, 1, 0, 1/4, 1)
     t                    x                h*f(t,x,y)                    y           h*g(t,x,y)
     0                    1                      0.00                    0                -0.25
   1/4                  1.0                    -0.062                -0.25                -0.23
   1/2                 0.94                     -0.11                -0.46                -0.17
   3/4                 0.88                     -0.15                -0.62                -0.10
     1                 0.75                     -0.17                -0.68               -0.015

AUTHORS:

  • David Joyner

sage.calculus.desolvers.eulers_method_2x2_plot(f, g, t0, x0, y0, h, t1)

Plot solution of ODE.

This plots the solution in the rectangle with sides (xrange[0],xrange[1]) and (yrange[0],yrange[1]), and plots using Euler’s method the numerical solution of the 1st order ODEs \(x' = f(t,x,y)\), \(x(a)=x_0\), \(y' = g(t,x,y)\), \(y(a) = y_0\).

Note

This function is for pedagogical purposes only.

EXAMPLES:

The following example plots the solution to \(\theta''+\sin(\theta)=0\), \(\theta(0)=\frac 34\), \(\theta'(0) = 0\). Type P[0].show() to plot the solution, (P[0]+P[1]).show() to plot \((t,\theta(t))\) and \((t,\theta'(t))\):

sage: from sage.calculus.desolvers import eulers_method_2x2_plot
sage: f = lambda z : z[2]; g = lambda z : -sin(z[1])
sage: P = eulers_method_2x2_plot(f,g, 0.0, 0.75, 0.0, 0.1, 1.0)
sage.calculus.desolvers.fricas_desolve(de, dvar, ics, ivar)

Solve an ODE using FriCAS.

EXAMPLES:

sage: x = var('x')
sage: y = function('y')(x)
sage: desolve(diff(y,x) + y - 1, y, algorithm="fricas")             # optional - fricas
_C0*e^(-x) + 1

sage: desolve(diff(y, x) + y == y^3*sin(x), y, algorithm="fricas")  # optional - fricas
-1/5*(2*cos(x)*y(x)^2 + 4*sin(x)*y(x)^2 - 5)*e^(-2*x)/y(x)^2
sage.calculus.desolvers.fricas_desolve_system(des, dvars, ics, ivar)

Solve a system of first order ODEs using FriCAS.

EXAMPLES:

sage: t = var('t')
sage: x = function('x')(t)
sage: y = function('y')(t)
sage: de1 = diff(x,t) + y - 1 == 0
sage: de2 = diff(y,t) - x + 1 == 0
sage: desolve_system([de1, de2], [x, y], algorithm="fricas")          # optional - fricas
[x(t) == _C0*cos(t) + cos(t)^2 + _C1*sin(t) + sin(t)^2,
 y(t) == -_C1*cos(t) + _C0*sin(t) + 1]

sage: desolve_system([de1, de2], [x,y], [0,1,2], algorithm="fricas")  # optional - fricas
[x(t) == cos(t)^2 + sin(t)^2 - sin(t), y(t) == cos(t) + 1]